(-2/5)+(3x/20)+(-3/10)=(x/5)+(x^2/4)-1

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Solution for (-2/5)+(3x/20)+(-3/10)=(x/5)+(x^2/4)-1 equation: 


x in (-oo:+oo)

(3*x)/20-2/5-3/10 = (x^2)/4+x/5-1 // - (x^2)/4+x/5-1

(3*x)/20-((x^2)/4)-(x/5)-2/5-3/10+1 = 0

3/10-1/4*x^2-1/20*x = 0

DELTA = (-1/20)^2-(-1/4*3/10*4)

DELTA = 121/400

DELTA > 0

x = ((121/400)^(1/2)+1/20)/(-1/4*2) or x = (1/20-(121/400)^(1/2))/(-1/4*2)

x = -6/5 or x = 1

x in { -6/5, 1 }

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